Question

(a) AABC, AB = 9 cm, BC = 12 cm and ZB = 90°
(b) APQR, 2Q = 90°, PQ = 8 cm and QR = 15 cm.
The hypotenuse of a right triangle is 65 cm and one leg is 25 cm. Find the length of the other
Two poles 25 m and 40 m high stand upright in a plauground If their foot ar 36​

Answer 1

Step-by-step explanation:

Let the perpendicular be x

According to pythagoras algorithm

h2 = p2+b2

(12)2cm = x2 + (9)2cm

x2= (12×12) +(9×9)cm

x2 =(144 + 81) cm

x2 =(125)cm

Then take out the root of 125 cm

$\sqrt{125cm}$

$\sqrt{5 \times 5 \times cm \times cm}$

25 cm

like this do the rest of the sums at your own

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