Question

A ∆ABC, AB = BC and < A=80° find < C

Answer 1

Step-by-step explanation:

If AB=BC,

Angle A=Angle C=> 80°.(angles opposite to equal sides are equal).

A+B+C=180°.

80°+80°+B=180°.

B=180°-160°

B=20°.

So, the angles of a triangle are : 80°, 80° and 20°.