A ABC - ADEF and the perimeters of AABC and ADEF are 30 cm
and 18 cm respectively. If BC=10 cm, then EF=.........
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∆ABC-∆DEF
pre(∆ABC)÷per(∆DEF)=BC÷EF
30÷18=10÷EF
1÷6=1÷EF
EF=6cm
The value of EF is 6cm
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