A accelerates from 6m/s to 16m/s in 10 second . calculate the distance covered by the car in that time .
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Answer:
u = 6m/s
v = 16m/s
t = 10s.
a = v-u/t
a = 16-6/10
= 10/10
a = 1m/s²
distance =?=s
We know that,
2as = v²-u²
2(1)(s) = (16)²-(6)²
2s = 256-36
2s = 220
s = 110
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