Question

A) acceleration between 0 to 4 sec.

B) acceleration between 4 to 8 sec .

C) total distance traveled.

D) net displacement .

E) average velocity. ​

Answer 1

Answer:

a) t=4 sec

v= 10

a=?

u=0

Explanation:

v=u+at

10= 0+ a×4

10/4= a

2.5m/s² = a

b) t= same as above

v= 0

u= 10

v= u + at

0 = 10+ a× 4

-10/4= a

-2.5 = a

its retardation = -2.5m/s²

c) s = area under graph

s1 = triangle

= height = 10

base = 8

1/2× 10×8

= 40 m

s2 = 1/2×5×1

s2= 2.5 m

s3= side × side

= 5×5 = 25m

total distance = s1+ s2+ s3

= 40 + 2.5 + 25

= 67.5 m

D) 0

E) average velocity = u+v/2

= 0+ 10/ 2

= 5m/s