Question

A
= AD
s= ut+-
(txat)
Solution:
We have been given
u= 0; v = 72 km h = 20 m sland
t = 5 minutes = 300 s.
(i) From Eq. (8.5) we know that
(V-u)
(nn) - b
at2
= 5 m s->
= 25 m +
= 37.5 m
The accelerati
and the dista
au
OR POSITION-V
20 ms - Om s-1
11
300 15
-ms2
15
ime graph sho
travelled by the
runiform accele
enclosed with
- the graph. The
(ii) From Eq. (8.7) we have
2 as = 02 - u2 = U2 - 0
Thus,
Example 8.7 TH
produce an
the opposite
the car tal
application
distance it
Solution:
We have
a=-6 m
From Eq.
U=U
ezium OABO
S=
2a
(20 ms )?
2x(1/15) ms
C = v and a
= 3000 m
0=1
olm​

Answer 1

Answer:

O=1bn,nbxmcbmfncjnfdnfnkfkfjkdk