A AD
to
A ABC is eight Angled at
prependicular
Boj I JA B-Scm,
BC = 13 cm
find the area
find the length of
and AC =
12 am
AD
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0
Answer:
In right angles triangle BAC, AB=5cm and AC=12cm
Area of triangle=21×base×height=21×AB×AC
=21×5×12=30cm2
Now, in ΔABC,
Area of triangle ABC=21×BC×AD
⇒30=21×13×AD
⇒ AD=1330×2=1360cm.
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