A aeroplane is flying horizontally with a velocity of 720km/h at altitude of 490m When it is just over above the target a bomb is dropped from it. How far horizontally it missed the target
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Answer:
1979
Explanation:
sx=uxt+1/2axt^2 ax=0
so,
s=720(2h/g)^1/2
720(5÷18)(2*490/10)^1/2
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