Question

a age is twice than b age.5 years ago his age was 3 times b age . Find their present ages​

Answer 1

Answer:

• The present age of A = 20 yrs.
• The present age of B = 10 yrs.

Step-by-step explanation:

Given,

• Age of A is twice the Age of B.
• Before 5 year, His age was three times of B.

To Find,

• Their present ages.

Solution,

Let's,

• The present age of B = x

So,

• The present age of A = 2x

Before 5 years,

• The age of B = x - 5

• The age of A = 2x - 5

According to Question,

• → 2x - 5 = 3(x - 5)
• → 2x - 5 = 3x - 15
• → 15 - 5 = 3x - 2x
• → x = 10

The value of x is 10 yrs.

The present age of A = 2x

• The present age of A = 20 yrs.

The present age of B = x

• The present age of B = 10 yrs.

Required Answer,

• The present age of A = 20 yrs.
• The present age of B = 10 yrs.