A air bubble rises from bottom of a lake to surface if its radius increases by 200% then atmospheric pressure equal to water
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Atmospheric pressure is 63 H.
Explanation:
According to Boyle's law:
P1V1 = P2V2
(h+H)(4/3πr1^3) = H(4/3πr2^3)
(h+H)(r1^3)=H(r2^3)
h+H/H = (r2/r1)^3
h/H+1=[(2(2)^3/r1)]
h/H=64 −1
h = 63 H
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