Question

A aircraft loops the vertical loop od radius 500 m

Answer 1

Explanation:

Given An aircraft loops the vertical loop of radius 500 m with a constant velocity v = 360 km/h. The weight of the flyer of mass m = 70 kg in the lower, upper and middle points of the loop will be respectively

• Now in a loop there are three conditions.There is a centrifugal force. So the weight will be the normal force in all the three conditions. Now we need to find the download force.
• So normal force N = mg + mv^2 / r
•                           = 70 x 10 + 70 x 100 x 100 /500  
•                              (v = 360 km/h = 360 x 5/18 = 100 m/s)
•                           = 700 + 1400
•                           = 2100 N
• Now Normal = mv^2/r
•                     = 1400 N
• In the third case we have N + mg + mv^2 / r
•                So N = mv^2/r – mg
•                        = 1400 – 700
•                       = 700 N
• So we get the lower, upper and middle points = 2100 N , 700 N, 1400 N

Reference link will be

https://brainly.in/question/16170407