A alone can complete a task in 18 days and B alone can complete that task in 15 days. How many days does it take to do the rest of the work after leaving B alone for 10 days?
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A can finish work in 18 days.
It means A can do the work in one day = 1/18 part
B can finish it in 15 days.
It means B can do the work in one day = 1/15 part
B worked alone for 10 days and then left the job
Thus in 10 days B has completed part of work =
1/15 × 10 = 10/15 part or 2/3 part of work
Remaining work left = 1 - 2/3 = 1/3 part of work remaining
A can do 1/18 part in one day
Therefore 1/3 part will be completed by him
= 1/1/18 × 1/3
= 1/3 × 18/1
= 18/3 days
= 6 days
A alone will complete the work in 6 days
Answer : A alone will finish the work in 6 days
aneesh9655:
nice
thanks
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I have used the unitary method for this. see this guys
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