a alone can complete a work in 36 days .b is 2/3 as efficient as a and if 7/9 of the work is done by a and b together then the remaining work is completed by c alone in 24 days . in how many days all the three will complete the whole work by working together.l
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Answer:
18 days
Explanation:
A can complete the work in 36 days.
Portion of work A can do in one day = 1/36
B is 2/3 as efficient as A.
There B can complete the work in 36÷2/3= 54 days.
Portion of work But can do in one day=1/54.
C complete (1-7/9) part of work in 24 days.
C completed 2/9 part of work in 24 days.
Therfore C can complete the work in (24÷2/9) =108 days.
Therefore portion of work C can complete in one day=1/108.
Therefore A, Band C together can complete in one day=(1/36) +(1/54) +(1/108)
=(3+2+1) /108=6/108=1/18.
Therefore A, B and C together can complete the work in= 1÷(1/18) days = 18 days.
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