A alone can do a piace of work in 8 days and B alone in 6 days. A start the work, work for 2 days and leaves the job. In how many days will B finish the remaining the work?
Answers
Answer:
A alone can do a piece of work in 8 days.
So, work done by A in one day = 1/8
Similarly, B alone do a piece of work in 6 days.
So, work done by B in one day = 1/6
Now,
Work done by both A and B is 1/8 + 1/6
=> 1/8 + 1/6
=> (3 + 4)/24
=> 7/24
A starts the work for 2 days and then leave.
We know that..
Work done by A alone is 8 days and in one day = 1/8
So, work done by A in 2 days = 1/8 × 2
=> 2/8
=> 1/4 part of the work
Remaining work = 1 - 1/4
=> (4 - 1)/4
=> 3/4
We have to find the number of days taken by B to complete the remaining work.
B alone do a piece of work in 6 days and remaining work is 3/4
So,
Work done by B to complete the remaining work = 3/4 × 6
=> 9/2 days
∴ In 9/2 days B complete the remaining work.
If you liked don't forget to follow me and mark me as Brainliest.