Question

A alone can do a piace of work in 8 days and B alone in 6 days. A start the work, work for 2 days and leaves the job. In how many days will B finish the remaining the work?​

Answer 1

Answer:

A alone can do a piece of work in 8 days.

So, work done by A in one day = 1/8

Similarly, B alone do a piece of work in 6 days.

So, work done by B in one day = 1/6

Now,

Work done by both A and B is 1/8 + 1/6

=> 1/8 + 1/6

=> (3 + 4)/24

=> 7/24

A starts the work for 2 days and then leave.

We know that..

Work done by A alone is 8 days and in one day = 1/8

So, work done by A in 2 days = 1/8 × 2

=> 2/8

=> 1/4 part of the work

Remaining work = 1 - 1/4

=> (4 - 1)/4

=> 3/4

We have to find the number of days taken by B to complete the remaining work.

B alone do a piece of work in 6 days and remaining work is 3/4

So,

Work done by B to complete the remaining work = 3/4 × 6

=> 9/2 days

∴ In 9/2 days B complete the remaining work.

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