Math, asked by veenamundra7, 2 months ago

A alone can do a piece of work in 12 days and B alone alone can do it in 15 days. what part of the work will they do in 3 days??​

Answers

Answered by ItzBrainlyGirl024
5

Answer:

A alone can do the work in 12 days he can do = 1/12 work in one day

B alone can do the work in 15 days

He can do = 1/15 work in one day

A works for 4 days

Work done = 4 × 1/12 = 4/12 = 1/3

work remaining = 1 - 1/3 = 2/3

A and B together can do = 1/12 + 1/15 = (5+4)/60 = 9/60 work in 1 day.

To finish the remaining work together, they need = (2/3) ÷ (9/60) = 2/3 × 60/9 = 40/9 days = 4 4/9 days

They need 4 4/9 days to finish the work.

PLZ MARK AS BRIANLIEST AND THX FOR THE SUPERB QUESTION

Answered by bhartirathore299
1

Answer:

hope so it will helpful to you

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