a alone can do a piece of work in 12 days and B alone can do the same work in15 days they started working together after 4 days B leaves the work in how many days A alone complete the remaining work
Answers
Answered by
4
Answer:
A's one day work = 1/12
B's. = 1/15
A+B's. = 1/12 +1/15=
5/60+4/6o=9/6o = 3/20
A+B's 4 days=4x3/20=3/5
Balance = 2/5
A will finish 2/5x12/1 = 24/5=4 4/5
days
Similar questions