A alone can do a piece of work in 12 days and B alone can do the same work in 15 days A works alone for 4 days in how many days will A and B together finish the remaining work
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Answer:
A's 1 day work =
12
1
A's 4 day work =
12
4
Remaining work =1−
12
4
=
12
8
=
3
2
B's 1 day work =
15
1
A and B can finish the work in =(12+15)×
3
2
=27×
3
2
=18
Hence A and B will together finish the work in 18 days.
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