Math, asked by anisasmal78, 3 months ago

A alone can do a piece of work in 12 days and B alone in 8 days. A and B start working together and B leaves the work after 2 days. If they received Rs. 4800 for the work, what will be the share of B?

Answers

Answered by vedantsah
2

Answer:

Answer in explanation. Please mark me as brainliast. Hope it helps.

Step-by-step explanation:

A's 1 day work =

12

1

A's 4 day work =

12

4

Remaining work =1−

12

4

=

12

8

=

3

2

B's 1 day work =

15

1

A and B can finish the work in =(12+15)×

3

2

=27×

3

2

=18

Hence A and B will together finish the work in 18 days. Please mark me as brainliast. Hope it helps.

Answered by probrainsme103
3

Concept

Multiplication means finding the product of two numbers. The number obtained after multpliying the numbers is known as product.

Given

A can alone do the work in 12 days and B can alone do in 8 days and they have received Rs.4800 for the work.

To find

The share of work if B leaves the work after 2 days.

Explanation

Suppose work contains 100 questions.

In 1 day questions that A can alone do=100/12

=8.33

In 1 day questions that B can alone do=100/8

=12.5

Now take the situation in wich A and B work together.

In 2 day questions that A does=8.33*2=16.33

In 2 day questions that B does=12.5*2=25

Payment will receive for 100 questions so the payment of 1 question=4800/100

=Rs 48.

Share of B=Payment of 1 question*Questions done by B in 2 days

=48*25

=Rs.1200

Hence the share of B is Rs.1200.

#SPJ2

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