Question

A alone can do a piece of work in 12 days . B do the sane work alone in 15 days . In how many days they A and B do the same work together​

Answer 1

Answer:

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Step-by-step explanation:

Consider eating 60 ( L.C.M of 12 and 15 - for easy canculation. You can assume any number) candies is the above said work.

A takes 12 days to eat 60 candies. ie, A eats 5 candies per day. Similarly, B eats 4 candies per day. Together they eat 9 candies per day.

They work together for 4 days. ie, 4 x 9 = 36 candies. Now 24 candies are left. These 24 candies have to be eaten by A only.

A eats 5 candies per day. So A will require 24/5 days to eat the remaining candies.

Answer 2

1st method:

A and B complete a work in = 15 days

One day's work of (A + B) = 115

B complete the work in = 20 days;

One day's work of B = 120

Then, A's one day's work

= 115−120 = 4−36 = 160

Thus, A can complete the work in = 60 days.

2nd method:

(A + B)'s one day's % work = 100/15 = 6.66%

B's one day's % work = 100/20 = 5%

A's one day's % work = 6.66 - 5 = 1.66%

Thus, A need = 100/1.66 = 60 days to complete the work.

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