Math, asked by bbhattacharyasaikat, 10 months ago

A alone can do a piece of work in 12 days. B, who is 60% more efficient than A, will finish work in?​

Answers

Answered by samitray
1

Answer:

7.5days

Step-by-step explanation:

A completes 1/12 work each day, B does 60% more that A

1/12X160/100 = 2/15 of work in 1 day

So number of days required by B = 15/2 = 7.5 days

Answered by YadhuKrishnan7050
1

Answer:

Hi...

Let the amount of work be done in 1 unit.

The efficiency of A will be = 1/12

B is 60℅ more efficient than A

=> 60℅ of A will be 1/20

so efficiency of B will be 1/20 + 1/12 = 1/7.5

So B can finish the work in 7.5 Days

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