A alone can do a piece of work in 12 days. B, who is 60% more efficient than A, will finish work in?
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Answered by
1
Answer:
7.5days
Step-by-step explanation:
A completes 1/12 work each day, B does 60% more that A
1/12X160/100 = 2/15 of work in 1 day
So number of days required by B = 15/2 = 7.5 days
Answered by
1
Answer:
Hi...
Let the amount of work be done in 1 unit.
The efficiency of A will be = 1/12
B is 60℅ more efficient than A
=> 60℅ of A will be 1/20
so efficiency of B will be 1/20 + 1/12 = 1/7.5
So B can finish the work in 7.5 Days
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