Question

a alone can do a piece of work in 35 days if b is 40% more efficient than a then we will finish the work in how many days​

Answer 1

A and B together will finish the work in 14.58 days.

Step-by-step explanation:

A can complete a piece of work in 35 days

So, work done by A in 1 -day = $\frac{1}{35}$

Since it is given that B’s efficiency is 40% more than A’s

i.e., B = A + [40/100] * A = A + (2/5)A = 7A/5

So, work done by B in 1 -day = $\frac{7}{5} * \frac{1}{35} = \frac{1}{25}$

∴ Work done by both A and B together in 1-day will be,

= $\frac{1}{35} + \frac{1}{25}$

= [5+7] / 175

= 12/175

Thus, both A and B will finish the work in 175/12 days or 14.58 days.  

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Answer 2

Step-by-step explanation:

A and B together will finish the work in 14.58 days.

Step-by-step explanation:

A can complete a piece of work in 35 days

So, work done by A in 1 -day =

1

35

35

1

Since it is given that B’s efficiency is 40% more than A’s

i.e., B = A + [40/100] * A = A + (2/5)A = 7A/5

So, work done by B in 1 -day =

7

5

∗

1

35

=

1

25

5

7

∗

35

1

=

25

1

∴ Work done by both A and B together in 1-day will be,

=

1

35

+

1

25

35

1

+

25

1

= [5+7] / 175

= 12/175

Thus, both A and B will finish the work in 175/12 days or 14.58 days.

----------------------------------------------------------------------------------------------------

Also View:

A can do a piece of work in 20 days and b can do it in 25 days .both of them finished the work and earned rs.3600.then a's share is?

https://brainly.in/question/1940583

A as 75% more efficient than b in how many days can a and b working together complete a piece of work which a alone takes 12 days finsh ?

https://brainly.in/question/9190442

A is 60% more efficient than b. in how many days will a and b together complete a piece of work if a alone can complete the work in 15 days ?

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