Question

'A' alone can do a piece of work in 35 days if b is 40 % more efficient than a then we will finish the work in how many days​?

Answer 1

Total work will finish together in $\frac{175}{12}$ days or 14.58 days.

Step-by-step explanation:

A alone can do a piece of work in number of days = 35

A alone can do work in one day = $\frac{1}{35}$

B is 40% more efficient than A.

So B alone can do work in one day = $\frac{1}{35}(\frac{140}{100})$

                                                           = $\frac{140}{3500}$

                                                           = $\frac{1}{25}$

If both work together, they will finish the work in one day

= $\frac{1}{35}+ \frac{1}{25}$

= $\frac{7+5}{175}$

= $\frac{12}{175}$  work in one day.

total work will finish together in $\frac{175}{12}$ days or 14.58 days.

Learn more time work problem : https://brainly.in/question/14466936