A alone can do a piece of work in 8 days. A and B together can finish the same in 6 days. if B alone is doing the work,how long will he take?
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Answer
Given
- A alone can do a piece of work in 8 days
- A and B together can finish the same in 6 days
Find
- Time required by B to finish the work
Solution
Let B takes "B" days to finish the work alone
Now ,
One day work of A alone
Given that , A alone can do a piece of work in 8 days
Thus ,
=> 1/8
One day work of B alone
We assumed B to finish the work in B days
Thus ,
=> 1/B
One day work when A and B work together
Given that, A and B together can finish the same in 6 days
Thus ,
=> 1/8 + 1/B = 1/6
=> 1/B = 1/6 - 1/8
=> 1/B = (4 - 3)/24
=> 1/B = 1/24
=> B = 24
- Hence B will take 24 days to finish the work alone
Answered by
1
Let B takes "B" days to finish the work alone
Now ,
One day work of A alone
Given that , A alone can do a piece of work in 8 days
Thus ,
=> 1/8
One day work of B alone
We assumed B to finish the work in B days
Thus ,
=> 1/B
One day work when A and B work together
Given that, A and B together can finish the same in 6 days
Thus ,
=> 1/8 + 1/B = 1/6
=> 1/B = 1/6 - 1/8
=> 1/B = (4 - 3)/24
=> 1/B = 1/24
=> B = 24
Hence B will take 24 days to finish the work alone
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