Math, asked by dolly7372, 4 months ago

A alone can do a piece of work in 8 days. A and B together can finish the same in 6 days. if B alone is doing the work,how long will he take?​

Answers

Answered by EliteZeal
22

Answer

Given

  • A alone can do a piece of work in 8 days
  • A and B together can finish the same in 6 days

Find

  • Time required by B to finish the work

Solution

Let B takes "B" days to finish the work alone

Now ,

One day work of A alone

Given that , A alone can do a piece of work in 8 days

Thus ,

=> 1/8

One day work of B alone

We assumed B to finish the work in B days

Thus ,

=> 1/B

One day work when A and B work together

Given that, A and B together can finish the same in 6 days

Thus ,

=> 1/8 + 1/B = 1/6

=> 1/B = 1/6 - 1/8

=> 1/B = (4 - 3)/24

=> 1/B = 1/24

=> B = 24

  • Hence B will take 24 days to finish the work alone

Answered by Ranveerx107
1

Let B takes "B" days to finish the work alone

Now ,

One day work of A alone

Given that , A alone can do a piece of work in 8 days

Thus ,

=> 1/8

One day work of B alone

We assumed B to finish the work in B days

Thus ,

=> 1/B

One day work when A and B work together

Given that, A and B together can finish the same in 6 days

Thus ,

=> 1/8 + 1/B = 1/6

=> 1/B = 1/6 - 1/8

=> 1/B = (4 - 3)/24

=> 1/B = 1/24

=> B = 24

Hence B will take 24 days to finish the work alone

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