Question

 A alone can do a work in 20days. B is 25% more efficient than A. A and B started working and worked for 4days. If C alone completed the remaining job in 22days. How many days C alone takes to complete the entire job?


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Answer 1

Answer:

40 days

Step-by-step explanation:

A alone can do work in 20 days.

B is 25% more efficient than A.

⇒ B can do a work in 16 days.

Let the total unit of work ( LCM of 20 and 16) = 80 units

⇒ A’s one day work = 4

⇒ B’s one day work = 5

As A and B left after working for 4 days.

⇒ Work done by A and B in 4 days = 36 work

⇒ Work left = 44 units is done by C in 22 days.

⇒ C’s one day work = 2 units

∴ 80 units of work can be completed by C alone in 80/2 = 40 days.

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