A alone can finish a piece of work in 40 days. B is 25% more efficient than a. C is 60% more efficient than b. In how many days a and c working together can finish the same piece of work ? (in days) adda
Answers
Answered by
1
A = 40 days
B = 25/100×40 =10
=> 40-10= 30 days
C = 60/100×30 = 18
=> 30-18 =12 days
A and C one day work = 1/40 + 1/12
=> 13/120
total days = 120/13 = (approx ) = 9 days
B = 25/100×40 =10
=> 40-10= 30 days
C = 60/100×30 = 18
=> 30-18 =12 days
A and C one day work = 1/40 + 1/12
=> 13/120
total days = 120/13 = (approx ) = 9 days
Similar questions