A alone can finish the work in 10 hours, B alone can finish the work in 12 hours and C alone can finish the work in 15 hours. A, B and C together started working at 11’o clock. After 2 hours A leaves. When will B & C will together will finish the work?
Answers
Answered by
1
In 10 Hrs A can finish = 1 work
In 1 Hr A can finish = 1/10 work
In 15 Hrs B can finish = 1 work
In 1 Hr B can finish = 1/15 work
In 1Hr (A + B) can finish = 1/10 + 1/15 work = 1/6 work
In 6 Hrs (A + B) can complete 1 work
Therefore, A and B together can complete the work in 6Hrs
Answered by
9
Answer:
4:20.
Step-by-step explanation:
Let the total work be = 60 (LCM of 10, 12, 15).
Work done per hour by A = 6, B = 5, C = 4.
Work done in 2 hours by A, B, C = 2*(6+5+4)/60 = 30/60 = 1/2.
Half of total work (60) is done, another half of work is done by B and C.
Remaining work is done by B and C in = 30/9 hours = 3 hr 20 min
Total time is = 2 hr + 3 hr 20 mins = 5 hr 20 min.
Work is completed by 11:00 + 5 hr 20 min = 4:20.
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