A alone completes a work in 10 days. A and B worked together for 3 days. A is 50% more efficient thanC. After A,C worked for 3 days, In how many days B alone finish this work if 13% work done?
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Step-by-step explanation:
Answer is 8 days (approximately).
Let W denotes the whole amount of work.
It is given that: (1) B can complete the work W in 30 days. (2) A is 50% more efficient than B. (3) C is 25% less efficient than B.
So we determine that,
(4) the number of days required by A to complete the work W = 30*(1 - 0.50) = 15
(5) the number of days required by C to complete the work W = 30*(1 + 0.25) = 37.5
Hence, in 1 day the amount of work done by A, B & C together
= W/15 + W/30 + W/37.5 = (W/15)*(1 + 1/2 + 1/2.5) = (W/15)*1.9 = (19/150)W
Therefore, the number of days required by A, B & C together to complete the work W = 150/19 = 7.895 = 8 (approximately)
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