Question

a amn throws a ball with a speed of 10 m/s. calculate the time after which it returns to the ground and also calculate the maximum height to reach​

Answer 1

Explanation:

$\blue{\mathfrak{\underline{\large{Given}}}:} \\ speed \: of \: ball(u)=10m {s}^{ - 1} \\ \blue{\mathfrak{\underline{\large{To \: find}}}:} \\ time \: taken \: by \: ball \: to \: reach \: the \: ground \\ and \: max \: height \: reach \\ \blue{\mathfrak{\underline{\large{Finding}}}:} \\ Time \: taken \: by \: ball \: to \: reach \: the \: ground \\ = \frac{2u}{g} \\ = \frac{2 \times 10}{10} \\ = 2s \\ Max \: height \: reach= \frac{ {u}^{2} }{2g} \\ = \frac{ {(10)}^{2} }{2 \times 10} \\ = \frac{100}{2 \times 10} \\ =5m \\ \red{\mathfrak{⟨\underline{\large{Hope \: It \: Helps \: You}}}⟩} \\ \blue{\mathfrak{⟨\underline{\large{Mark \: Me \: Brainliest}}}⟩}$