Question

A & B are friends. A is elder to B by 5 years. B's sister C is half the age of B. If the present age of D is 48 years. Find the present ages of A, B & C

Answer 1

Answer:

Let C=X

B=2X

A=2X+5

D=2×2X+8

=4X+8

Here D is given as 48

Therefore,

4X+8=48

4X=40

X=10

Therfore

Age of C = 10

Age of B = 20

Age of A = 2×10+5

=25

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