A&B are square matrices of order 3 each |A|=2&|B^(T)|=3 .Find |-4AB| .
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We know that
∣AB∣=∣A∣∣B∣
Also for a square matrix of order 3
∣KA∣=K
3
∣A∣because each element of the matrix A is multiplied by k and hence in this case we will have k
3
common.
∴∣3AB∣=3
3
∣A∣∣B∣=
=27(−1)(3)=−81
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