Question

A&B are sub set of n(U)=700,n(A)=200,n(B)=300,find n(A'nB')

Answer 1

Answer: $n(A'\cap B')=300$

Step-by-step explanation:

Since we have given that

A and B are subsets

$n(U)=700\\\\n(A)=200\\\\n(B)=300$

As we know the formula for "Set Rules ":

$n(A\cup B)=n(A)+n(B)-n(A\cap B)\\\\n(A\cup B)=200+300-(300-200)\\\\n(A\cup B)=500-100\\\\n(A\cup B)=400$

but we need,

$n(A'\cup B')=n(U)-n(A\cap B)\\\\n(A'\cup B')=700-400\\\\n(A'\cup B')=300$

Hence, $n(A'\cap B')=300$

Answer 2

Answer:

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