A & B can do a piece of work in72 days, B&C can do the same work in 120 days, wheras A & C can do that work in 90 days, if A, B&C work together how much piece work they can finish after 3 days?
Answers
Answer :-
They all together complete the 20th part of the work in 3 days.
Step-by-step explanation:
A and B do a piece of work in 72 days.
So, work done by A and B in one day =
Similarly,
B and C do a piece of work in 120 days and A and C do that work in 90 days.
So,
Work done by B and C in one day =
And work done by A and C in one day =
We have to find the work done by A, B and C all together in 3 days.
Now,
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•°• A, B and C together finish the work in 60 days.
But we have to find the work done by A, B and C all together in 3 days.
So, for 3 days :
Work done by A, B and C in 3 days =
= 20
•°• A, B and C together complete the 20th of the work in 3 days.
Answer:
A & B do work in = 72 days
Therefore, A & B do amount of work in one day =
B & C can do work in= 120 days
therefore, B & C do amount of work in one day =
A & C can do work in= 90 days
therefore, A & C do amount of work in one day =
Now, sum of the work done by all in one day,
- A + B = 1/72
- B + C = 1/120
- A + C = 1/90
- (A + B) + (B + C) + (A + C) = 1/72 + 1/120 + 1/90
- 2(A + B + C) =
- A + B + C =
- A + B + C =
- A + B + C = 1/60
therefore, A, B & C can do 1/60 amount of work in one day.
If they work together, they can finish piece of work in 3 days =
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