Question

A & b together can do a piece of work in 12 days, which b & c together can do in 16 days. after a hasbeen working at it for 5 days and b for 7 days c finishes it in 13 days. in how many days c alone will do the work?

Answer 1

Solution:-
(A+B)'s one day work =1/12
(B+C)'s one day work=1/16

A's 5 day work +B's 7 day work+ C's 13 day work=1
A/q
$= > \frac{5}{12} + \frac{2}{16} + c \: 11days \: work = 1$
c 11 days work=
$= > 1 - ( \frac{5}{12} + \frac{2}{16} ) \\ = > 1 - \frac{13}{24} \\ = > \frac{11}{24}$
C's one day work=
$= > \frac{11}{24} \times \frac{1}{11} \\ = > \frac{1}{24}$
Hence,C can finish the work in 24 days.