Question

∆A an ∆B are Supplementary angles It ∆A=x10°and∆B=x-10° Find the angles ∆Aand∆B​

Answer 1

Answer:

A=x+10

∘

,∠B=x−10

∘

Given ∠A and ∠B are supplementary angles

⟹x+10

∘

+x−10

∘

=180

∘

⟹x=90

∘

∠A=90

∘

+10

∘

=100

∘

∠B=90

∘

−10

∘

=80

∘

Answer 2

Solution

∠A=x+10∘,∠B=x−10∘

Given ∠A and ∠B are supplementary angles 

⟹x+10∘+x−10∘=180∘⟹x=90∘

∠A=90∘+10∘=100∘

∠B=90∘−10∘=80∘