A an dB can do a piece of work in 16 days and A along can do it in 24 day, how long will how long will' 'B' alone take to complete the work
Answers
Answered by
1
Answer:
A very easy and simple trick.
A+B=16 days
A=24 days
So, let's take LCM of 16 and 24. That's 48.
Step-by-step explanation:
This 48 unit is the total work to be done.
So, A and B do (48/16) = 3 unit work/day …(1)
And, A does (48/24) = 2 unit work/day …(2)
Equation(1)-(2)
{A+B-A=3–2=1}
B does (3–2)= 1 unit/day
So, Total days required = (Total work)/(unit per day)
That is B can do it in (48/1)=48 days.
Answered by
0
Answer:
48 days
Step-by-step explanation:
Time taken by A and B = 16 days
A and B together one day work =
Time taken by A alone = 24 days
A alone one day work =
B alone one day work
= (A and B together one day work) - (A alone one day work)
=
=
=
Time taken by B alone
= 1 ÷ One day work
= 1 ÷
= 48 days
Similar questions