(a)An electric iron of resistance 30 Ω takes a current of 6 A. Calculate the heat
developed in 60 s.
(b)How can three resistors of resistance 4Ω , 5Ω and 6 Ω be connected to give a total
resistance of (i) 3.6 Ω , (ii) 8.23 Ω
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a) Given, r=30ohm, I=6A and t= 60s
we know that, the formula of heat
Heat = (I)2 RT
= 6x6x30x60
= 64800j
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