(a) An element has a bcc structure with a cell edge of
288 pm. The density of the element is 7.2 g/cm'. How
many atoms are present in 208g of the element?
Answers
Answer:
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Explanation:
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12th
Chemistry
The Solid State
Packing Efficiency and Calculations Involving Unit Cell Dimensions
An element has a body cente...
CHEMISTRY
An element has a body centered cubic (bcc) structure with a cell edge of 288 pm. The density of the element is 7.2g/cm
3
. How many atoms present in 208g of the element.
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ANSWER
Volume of unit cell =(288 pm)
3
=(288×10
−10
cm)
3
=2.389×10
−23
cm
3
Volume of 208 g of the element =
Density
Mass
=
7.2
208
=28.89 cm
3
Number of unit cells =
Volume of a unit cell
Total Volume
=
2.389×10
−23
28.89
=12.09×10
23
For a BCC structure, number of atoms per unit cell =2
∴ Number of atoms present in 208 g = No. of atoms per unit cell × No. of unit cells
=2×12.09×10
23
=24.18×10
23
=2.418×10
24
Answer:
2.24 * 10^24
Explanation:
- 2.24 * 10 ^24