Math, asked by simran5780, 6 months ago

(a) An empty cistern can be filled by two pipes A and
B in 12 minutes and 16 min respectively and the
full cistern can be emptied by a third pipe C in 8
min.If all the pipes be turned on at the same time,
in how much time will the empty cistern be full?
1:​

Answers

Answered by kishna9966singh
1

Answer:

Sorry I can't give you the answer of this question

Answered by ahannank19
0

Answer:

120 min

Step-by-step explanation:

Pipe a = 12 min

Pipe b = 16 min

Pipe c = 8 min ( emptying )

Pipe a in 1 minute = 1 / 12

Pipe b in minute = 1 / 16

Pipe c = 1 / 8

a and b fill, c empties

So,

1 / a + 1 / b - 1 / c = Tank filled in one minute

1 / 12 + 1 / 16 - 1 / 8

LCM = 48

4 / 48 + 3 / 48 - 6 / 48

4+ 3 - 6 / 120

1 / 120 = Filled in one minute

Total time = 120 / 1

Total time taken to fill the cistern = 120 minutes ( approx

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