(a) An empty cistern can be filled by two pipes A and
B in 12 minutes and 16 min respectively and the
full cistern can be emptied by a third pipe C in 8
min.If all the pipes be turned on at the same time,
in how much time will the empty cistern be full?
1:
Answers
Answered by
1
Answer:
Sorry I can't give you the answer of this question
Answered by
0
Answer:
120 min
Step-by-step explanation:
Pipe a = 12 min
Pipe b = 16 min
Pipe c = 8 min ( emptying )
Pipe a in 1 minute = 1 / 12
Pipe b in minute = 1 / 16
Pipe c = 1 / 8
a and b fill, c empties
So,
1 / a + 1 / b - 1 / c = Tank filled in one minute
1 / 12 + 1 / 16 - 1 / 8
LCM = 48
4 / 48 + 3 / 48 - 6 / 48
4+ 3 - 6 / 120
1 / 120 = Filled in one minute
Total time = 120 / 1
Total time taken to fill the cistern = 120 minutes ( approx
Similar questions