Question

a)An equiconvex lens of focal length f is cut into two identical plane convex lenses.How will the power of each part be related to the focal length of the original lens?
b) A double convex lens of +5 D is made of glass of refractive index 1.55 with both faces of equal radii of curvature. Find the value of its radius of curvature.
Pls answer it.​

Answer 1

Answer:

focal length of original lens = f

focal length of each lens when cut into two pieces = F

1/f = 1/F + 1/F

1/f = 2/F

2f = F

power of each piece

P = 1/F

P = 1/2f