(a) An object is moving with uniform speed in a circle of radius 7m. Calculate the distance and displacement when it completes half the circle. What type of motion does the object possess? (c) A particle is travelling in a circle of diameter 15m. (d) Calculate the distance covered and the displacement when it completes two rounds.
Answers
Answer:
is it clear
if not ask me i will clear
a. Given radius (r) is 7 m
Finding distance
Distance is the total path travelled by the body
Therefore here distance= Circumference of circle
Formula for circumference of a circle is 2πr
=2*(22/7)*7
=44m
Therefore distance covered is 44/2( Since it is a semi circle)
=22m
Therefore distance covered by the body is 22m.
Finding displacement
Displacement is the shortest distance
Therefore here displacement= The diameter of the circle
=2r
=2*7
=14m
The object possesses uniform circular motion
c.
Given diameter (d) is 15 m
Therefore r=d/2 (Since d=2r)
=15/2
=7.5m
Finding distance
d. Distance is the total path travelled by the body
Therefore here distance= Circumference of circle
Formula for circumference of a circle is 2πr
=2*(22/7)*7.5
=47.14m
Therefore distance covered is 47.14*2( Since body covers distance of 2 times the circle )
=94.28m
Therefore distance covered by the body is 94.28m.
Finding displacement
Displacement is the shortest distance
Therefore here displacement= Final position-Initial position
=0m