a)
An object of 40 kg mass is moving with 5 m/s velocity. Now force is applied
on the object such that its velocity increases to 10 m/s. Calculate the work
done by the force.
Siente in den
Answers
Answer:
Work done can be calculated as follows:
W=△K.E
W=
2
1
m(v
2
−u
2
)
=
2
1
×40(5
2
−2
2
)
=20(5+2)(5−2)
=20×7×3=420J
Explanation:
hope it helps plz mark as brainliest
Answer:
Work done = 1875J ★
Explanation:
Given:
Mass of object is 40 kg
Initial velocity (u) is 5m/s
Final velocity (v) is 10m/s
To Find:
Work done by the force
Solution: We know that
★ Work done= Force x Displacement ★
W = F x S
★ Force = Mass x Acceleration ★
F = M x a
† We can write a = F/m
→ By the third equation of the motion ←
v² – u² = 2as
⟹ 10² – 5² = 2as
⟹ 100 – 25 = 2 x F/m x s ( Since, a = F/m )
⟹ 75 = 2 x F/50 x s
⟹ 75 = F/25 x s
⟹ 75 x 25 = F x s
⟹ 1875 = F x s
⟹ W = F x S
Hence, Work done by the force is 1875J
__________________________________
★ Solving through another method ★
Given:
Mass is 50 kg
Initial velocity (u) is 5m/s
Final velocity (v) is 10m/s
To Find:
Work done by the force
Solution: According to the work energy conservation theorem
★ Work done by the Force= Change in Kinetic Energy ★
Work done by the Force = 1/2 x m ( v² – u² )
⟹ Work done = 1/2 x 50 x ( 100 – 25 )
⟹ Work done = 25 x 75
⟹ Work done = 1875 J
Hence, Work done by the force is 1875J