A. an object of mass 500g begins from rest and attains a velocity of 25m/s in 10 seconds. calculate i) the change in its momentum ii) the force applied to make this change.
Answers
Answered by
0
Explanation:
Mass of object = 500gm = 1/2 kg
initial velocity = 0 m/s
final velocity = 25 m/s
time = 10 sec
I) Change in momentum
P initial = m × u
P = 1/2 kg × 0 => 0 kg.m/s ..(1)
P final = m × v
P = 1/2 kg × 25 m/s = 25/2 kg.m/s ...(2)
So change in momentum
∆P = P1 - P2
= 25/2 - 0 => 25/2 kg.m/s
u = 0 ; v = 25m/s ; t = 10 sec
therefore,
a = ∆v/t ==>. 25/10 ==> 2.5 m/s²....(3)
we know that,
F = m×a
therefore,
F = 1/2kg × 2.5 m/s²
therefore force applied to make the change is
F = 1.25 kg.m/s²
.
.
.
Therefore,
Change in momentum = 25/2 kg.m/s
= 12.5 kg.m/s
Force = 1.25 kg.m/s²
If you think I was right, surely mark it as brainliest
Similar questions