A) an optically active compound having molecular formula c7h15br reacts with aqueous koh to give c7h15oh, which is optically inactive
Answers
Answered by
10
The question seems to be incomplete since the requirement for the answer is not given clearly. So, I am giving a generally assumed answer in which I am giving the mechanism of the above-given reaction.
C₇H₁₅Br → C6H₁₅C⁺ (Carbocation) + Br⁻.
The C₆H₁₅C⁺ formed in the reaction is a carbocation, which means that the central Carbon atom will form 3 bonds with other atoms and will have one positive charge instead of having formed another bond.
Upon reaction with aqueous KOH, the carbocation forms C₇H₁₅OH. The product is C₇H₁₅OH is formed as a racemic mixture in which one has a retention configuration and the another with inversion of configuration is formed. The product obtained is obtained as a racemic mixture which is optically inactive.
The attachment shows the structures of the racemic mixture products.
C₇H₁₅Br → C6H₁₅C⁺ (Carbocation) + Br⁻.
The C₆H₁₅C⁺ formed in the reaction is a carbocation, which means that the central Carbon atom will form 3 bonds with other atoms and will have one positive charge instead of having formed another bond.
Upon reaction with aqueous KOH, the carbocation forms C₇H₁₅OH. The product is C₇H₁₅OH is formed as a racemic mixture in which one has a retention configuration and the another with inversion of configuration is formed. The product obtained is obtained as a racemic mixture which is optically inactive.
The attachment shows the structures of the racemic mixture products.
Attachments:
Similar questions