A an saved ₹32 during the first year ,₹36 in the second year and in this way he increases his savings by₹4 every year. Find in what time his saving be ₹200
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A=32
D=36-32=4
Tn =200
32+(n-1 )4=200
N-1=(200-32)÷4
N-1=168÷4
N=42+1
N=43
D=36-32=4
Tn =200
32+(n-1 )4=200
N-1=(200-32)÷4
N-1=168÷4
N=42+1
N=43
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