Question

a and 1/a are the two zeros of the polynomial p(y)=4-k-y+2y^2 find the value of k ​

Answer 1

Answer:

Given α,

α

1

are the zeroes of 4x

2

−17x+k−4

As we know that

Product of zeroes of quadratic polynomial ax

2

+bx+c is

a

c

Here c=k−4,a=4

⟹α×

α

1

=

4

k−4

⟹1=

4

k−4

⟹k−4=4

⟹k=4+4

⟹k=8

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