A and B alone can do a work in 20 days and 30 days respectively they worked together for some time after that b left if a does the remaining work in 10 days then for how many days b worked?
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A completed a work in 20 days
And B completed that work in 30 days
Hence, when they worked together then after some time B left.
So A do that work 20+10=30
And B before left he do work only 20 days. Hence B work 20 day.
Answered by
1
Answer:
ANSWER is 6 days.......
Step-by-step explanation:
In 1day A can do=(1/20) part of the work
In 1day B can do=(1/30) part of the work
In 1day (A+B) can do
=[(1/20)+(1/30)] part of the work
=(5/60)
=(1/12)
Let they togetherly worked for x days...
Then wokdone by (A+B) in x days=(x/12)
Now, wokdone by A in 10 days=(10/20)=1/2
Now,
total work=1
(x/12)+(1/2)=1
x+6=12
x=6
i.e., B worked for 6 days
Hope you have understood.....................
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