A and B are 2 digit consecutive numbers such that the unit digit of A^2 is 6 and the unit digit of B^2 is 5 then the number of all possible non perfect square numbers between A^2 and B^2 is?
A:1872
B:1962
C:1982
D:2022
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Answer:
Correct option is B)
Step-by-step explanation:
The second, sixth and the ninth digit of the number 187642539 is 8, 2, 9 respectively.
The perfect square that can be made with these digits is 289 which is a perfect square of the odd number 17.
Therefore, the unit digit is 7.
I hope it is helpful of you
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