Question

A and B are 2 pulleys the length AB=5cm A 5 kg mass is suspended by using 2 strings of length 3m and 4m.The string from pulleys A makes an angle​

Answer 1

Answer:

Lets do an Free body diagram of m

1

=5kg

T is acting upwards whereas m₁g is acting downwards.

m

1

g>T (m

1

>m

2

)

Free body diagram of m

2

=3kg

T is acting upwards whereas m

2

g acts downwards.

m

2

g<T

m₁g-T=m₁a----------------(i)

T₂-m₂g=m₂a--------------(ii)

add (i) and(ii)

m

1

g−m

2

g=m

1

a+m

2

a

g(m

1

−m

2

)=a(m

1

+m

2

)

10(2)=a(8)

20=8a

20/8=a

a=2.5m/s

2

For finding T

T−m

2

g=m

2

a

T−30=7.5

T=37.5N

Therefore Force on pulley by rope =2×Tension

Force on pulley=37.5N×2

force=75N

Hence,

option (B) is correct answer.