A and B are 2 pulleys the length AB=5cm A 5 kg mass is suspended by using 2 strings of length 3m and 4m.The string from pulleys A makes an angle
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Answer:
Lets do an Free body diagram of m
1
=5kg
T is acting upwards whereas m₁g is acting downwards.
m
1
g>T (m
1
>m
2
)
Free body diagram of m
2
=3kg
T is acting upwards whereas m
2
g acts downwards.
m
2
g<T
m₁g-T=m₁a----------------(i)
T₂-m₂g=m₂a--------------(ii)
add (i) and(ii)
m
1
g−m
2
g=m
1
a+m
2
a
g(m
1
−m
2
)=a(m
1
+m
2
)
10(2)=a(8)
20=8a
20/8=a
a=2.5m/s
2
For finding T
T−m
2
g=m
2
a
T−30=7.5
T=37.5N
Therefore Force on pulley by rope =2×Tension
Force on pulley=37.5N×2
force=75N
Hence,
option (B) is correct answer.
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