Math, asked by vishwakamal01, 2 months ago

a and b are 50 and 70 years old how many years ago was ratio of their ages 2:3​

Answers

Answered by ajaythakkar1982
7

Answer:

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Step-by-step explanation:

Present age of Saransh =50 years

Present age of Nazma =40 years

Let us consider that x years ago their ages were in ratio of 3:2, Therefore,

(50-x)/(40-x)=3/2

On solving, we get x=20

So, 20 years ago when the age of Saransh was 30 years and Nazma was 20 years old their ages were in the ratio of 3:2

Answered by Anonymous
1

Given : A and B are 50 and 70 years old.

To find : How many years ago was the ratio of their ages 2:3?

Solution :

We can simply solve this mathematical problem by using the following mathematical process. (our goal is to calculate the required number of years)

Let, the ratio of their ages was 2:3 = x years ago

So, x years ago :

  • Age of A = present age - x = (50 - x) years
  • Age of B = present age - x = (70 - x) years

According to the data mentioned in the question,

(50 - x) : (70 - x) = 2:3

(50 - x) / (70 - x) = 2/3

3 × (50 - x) = 2 × (70 - x)

150 - 3x = 140 - 2x

-3x + 2x = 140 - 150

-x = -10

x = 10

So, the ratio of their ages was 2:3 = x years ago = 10 years ago

(This will be considered as the final result.)

Hence, 10 years ago, the ratio of their ages was 2:3

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