A and B are acute angles of a right angled ∆ABC . Prove that tan²A - tan²B = sin²A- sin²B /cos²A x cos²B
Answers
Answered by
1
Answer:
Step-by-step explanation:
A and B are acute angle of a right angled triangle
Therefore,90+A+B=180 degree
A+B=90
B=90-A......1
Substituting 1 in the question
LHS
Tan^2 A - tan^2 (90-A)
Tan^2 A - cot^2 A
Sin^2 A - cos^2 A/sin^2 A cos^2 A
RHS
sin^2 A - sin^2 (90-A)/cos^2 A × cos^2 (90-A)
sin^2 A - cos^2 A/ cos^2 A × sin^2 A
LHS=RHS
HENCE PROVED
kareenah:
may i ask u a doubt?
Similar questions